@Ted Yapo  he wanted to know; "Can you verify/estimate that this spectrum is close to a 6500K color temperature?"

And the answer is yes, in RSpec I just figured it out, so I'll just get right to it and then explain the concepts behind it afterwards.

Ok, there's a lot going on here, 1st is the Planck's spectral blue line, which is our "black body," this is our reference spectra @ 6500k. My CFL lamp has been calibrated to this reference and is accurate because my spectrometer has already been calibrated for instrument response.

To the far left you see the 2nd Y axis Refer. This is our ratio between red and blue light, because blue is our shorter wavelength which are hotter and red are longer wavelengths which are much cooler. Since we can use the computer to do the math we can use wavelength's as our measurements instead of blue and red filters.

We convert Angstroms to Nanometers and get 447nm for blue and 616nm for red, these are the calibration points. The program already did the calculations and found the ratio to be 1.050 but on my calculator I got 1.055? The difference between 6500k and 6160.

This is not written in stone mind you, but is still accurate because the temperature of any bulb will change somewhat ( called "drift") over time. just like the Sun does, it's temp (surface,) is around 5400K but changes because of many variables.

Above are both my 2300k and 6500k CFL bulbs, I didn't bother calculating the 2300k bulb as I felt it was irrelevant. Still a good comparison since both are at the same intensity. You notice the 6500k CFL's blue zone is much hotter than the 2300k's CFL. That's the manufacturer trying to simulate daylight...Ha!

Not that I'm giving a shameless plug to the Solux company, but their Halogen bulbs are far superior in these regards.

I hope this helped answer your question Ted, and anyone else out here that is interested in this subject :)