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Asynchronous serial reception

A project log for Discrete YASEP

a 16-bits YASEP computer (mostly) made of DIP/SOIC chips like in the 70s and 80s... with 2010's twists!

Yann Guidon / YGDES 10/22/2015 at 23:122 Comments

At this point, I "can" (read: know how I could) send data from the P1B board to a USB-serial dongle with relatively few gates. Now I must find how to do the reverse to receive data on P1A.


Flashback

I still remember building a UART board as one of my first PCBs, around 1991, as an unexperienced teen. I used a AY-3-1015D integrated UART (DIP40) found at RadioShack. It never worked but "I learnt a few things" along the way.

Other hackers have followed this route before, one of the last being @matseng

"Well, every journey has to have a beginning so I started of with a relatively simple part of the entire system - the UART."

But as I understand it, his receive system uses an "analog hack" that is too delicate to calibrate.


Back to 20151022

I got the clock and I got tens of 74HC595. I could even make a shift register with a 74HC574 or 74HC293. I have also already written 2 working serial receive circuits in VHDL so it shouldn't be hard to design another with TTL-style logic. But for this project I don't have the luxury of spawning arbitrary logic with a few key presses and some clicks.

The shift register is only the easy part of the story. Serial reception is classically the domain of finite state machines, with counters peppered here and there. Furthermore, that kind of circuit has to work with several clock granularities because

  1. If you have an existing clock at the right baud rate, it doesn't matter because the sender certainly is phase-shifted. We can forget the baud generator of board P1B.
  2. You need a main clock that is a multiple of the baud rate (we got it already)
  3. You have to divide this clock again to get the baud rate, but you have to synchronise it "somehow", so it runs with the right phase.
  4. Oh and once synchronised, actual data synchronisation happens by delaying the shift clock by half a bit-time, not a full bit time, so you have to handle two durations...

Let's add another constraint. No, I don't care about parity (we're doing 1 start and 1 stop bit only). To increase reliability, the start bit must be low during a whole half cycle. Only then can we start shifting data in.

In my VHDL designs, I reduce the complexity and save a few gates with a little neat trick : the shift register is reset to all 1s before shifting the start bit in. When the last bit of the shift register is reaching "0" we know that all the data bits are shifted in. Then we just have to check the value of the stop bit, if it reads as "1" then the byte is valid.

With the '595 or the '273, the CLR pin clears the registers to 0. This inverts the whole logic but it is still possible : just OR the data input pin at the right moment, to make the start bit look like 1. The shift will end when the last bit (at the other end of the shift register) changes from 0 to 1.

The choice of the part will depend on whether I'll need the '595's tristate output.

The "shift trick" is useful in VHDL because I want to keep the gate count as low as possible. However I can instantiate as many bits in the shift register but I can't hold the necessary 9 bits in the '595 or the '273.

With this discrete system, I might as well use another CD4040 with its extra divider stages and they can be used as a substitute for a proper finite state machine.

In fact, this counter also looks like the digital analog to the ramp in @matseng's design. If we tap and combine the right signals, it becomes possible to sequence the right pulses at the right times, and its digital nature makes it immune to later baud rate modifications.


My VHDL code normally handles a few transitions (hence states)

  1. Idle/waiting
    -> if the data input is low,
    -----> the baud counter is initialised to half a bit period and goto state 2
  2. START bit validation : decrement the baud counter
    -> if data input is 1 then return to state 1
    else
    -----> if counter expired then init baud counter to bit time and goto state 3
  3. SHIFT state : decrement the baud counter
    -> if counter expired then
    -----> if shift register is full,
    ---------> check the value of the stop bit, buffer the register's data and goto 1.
    -----> else
    ---------> shift another bit in the shift register and init baud counter to bit time

This is a 3-states machine with 1 count-down baud counter and minimal random logic. Maybe I can come up with something else using a CD4040 ? Let's see...

The '595 and the '273 latch on a rising clock edge. If we look at the right output stage of the CD4040, this corresponds to the half time of a bit period (and if not, we can still complement the clock bit).

It is possible to drive the shift register with a 180° phase, relative to the baud clock running after the CLR pin is released (end of reset). The big difference with FPGA design techniques is that we can play with reset and clock lines, both these resources are constrained inside a FPGA fabric and clock gating often penalizes performance or gate count.Here we are free from the constraint of a single-clock synchronous design rule.

Another "trick" for the START bit detection : we can use the serial data input to control the counter's reset line (after a NOT because CLR is active low). This starts the counter from 0 when a falling edge appears. After a while, one of the outputs (here, the 115200) goes high and we can use this information to say "we got a long enough low pulse".

So we have detected the start pulse but the rest is possible only if we can keep the CLR input from going low again, at least not until we have shifted everything in. A feedback gate is necesary.

The final circuit doesn't implement the "short START bit detection" because it is too unlikely to happen. Instaed I have built the control circuit around a synchronous RS structure where reset has priority over set. The delay that the DFF gate adds keeps the output signals clean with fixed 300ns transients/pulses at the output of the AND3 gate, which can trigger other circuits.

The principle is simple :

This design is not the best but it's simple, cheap, works "in nominal conditions" and uses only available simple gates.

The SET/RESET logic (OR-AND) can be reduced to a single 3input gate, such as some modern SOT23 gates.

The circuit does not reset if short pulses are present but the input DFF resamples Din to protect against very short transients. It's a good compromise.


Found at http://digitarworld.uw.hu/circuits.html:


Discussions

Andrew Starr wrote 11/03/2015 at 05:57 point

Cool, looks like there'll be a discrete UART design for me to plagarise when the time comes :)

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Yann Guidon / YGDES wrote 11/03/2015 at 08:48 point

I'd be very curious to see your "rip off" ;-)

However I believe you should use a different design, inspired by my VHDL version instead, because we have different sets of constraints.

If you can have "reset to 1" DFF gates, then the "shift register trick" better for you. That would be 9 or 10 DFF1 for the shift register, the last in the chain being the "finished" flag when it goes to 0 (as it outputs the start bit). You could use ×8 oversampling to reduce the number of Div2 gates, with a lower main clock frequency that is an exact multiple of the serial speed (in my VHDL design I divide a non-multiple, higher frequency like 50MHz so the counter design is more complex).

Maybe I could help you design the serial receive unit, if you haven't done it yet. You'll need DFF gates that reset to 1 and 0 though. I'll see what I can do...



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