Many years ago when I was designing an infrared camera slave pointing system the cost of an infrared receiver IC (integrated circuit) was about $7. This IC was TTL (Transistor Transistor Logic) with three pins. Power, Output and Ground. Then the price increased to about $8 which when I actually purchased this IC in late 2002. I also obtained a copy of the datasheet from the electronics store. However, the printing was very low quality and this is why I could not read the pins properly. I must have made a mistake with the pins and partially burned this IC. The IC was receiving the infra red signal well. However, it had a weak output drive because I have partially burned it.
Nowadays the cost is only about $3. This make this ICs appropriate for cheap circuits.
Here is the video of the circuit working:
First I read the following articles about old fashioned transistor amplifier circuits that can be used to amplify signals from infrared sensors:
https://www.instructables.com/id/Transistor-Sensor-Amplifier/
https://www.instructables.com/id/Recycled-Transistor-Amplifier/
I designed the circuit with the ZD1953 IC and a simple PNP BJT (Bipolar Junction Transistor) inverter.
Step 1: Make the Circuit
Two transistors were placed in parallel to improve reliability and increase device life time. However, using a second transistor is not necessary. The circuit can still work well with one transistor. You also might not need a second 1 kohm resistor either. The two 1 kohm resistors are connected in series to reduce the maximum transistor base current.
From top to bottom the pin layout is:
1. Output (connected to 1 kohm resistor)
2. Ground (blue wire)
3. 5 V Power Supply for TTL (red wire)
The PNP transistor collector is connected to four LEDs in parallel with the blue 100 ohm resistor. The voltage potential is:
VoMax = Vled + Vr
= 2 V + 100 ohms * 25 mA = 4.5 V
There are four LEDs. Each LED will receiver about 6.25 mA of current. Those LEDs are made to consume 5 mA.
Suppose we raise the power supply to 6 V:
VoMax = Vled + Vr
= 2 V + 100 ohms * 40 mA = 6 V
Each LED will receive about 10 mA of current.
I placed the circuit in a plastic container because I did not want to pay for the box.
Step 2: Testing
I used my infrared transmitter to keep the LEDs ON long enough so that I could take a photo:
You can see my transmitter sending the signal to the infrared sensor:
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