# Laser Calibration 1

bob wrote 01/26/2021 at 02:46 • 3 min read • Like

# Laser Power Calibration

If we're going to do anything useful with our test setup, it's necessary to know the power of our laser.

We used four methods to measure the laser power. Each of the methods has its 'issues' but they agree closely enough to give us some confidence in the results.

 Method Laser Power Light Dependent Resistorcompared with bright sunlight 0.1 mw Photodiodecompared with bright sunlight 0.15 mw Photodiodebased on specifications 0.27 mw Camerabased on specifications 0.1 mw

## Light Dependent Resistor (LDR)

We compare the response of a LDR to the laser and to the bright sun.

Why the sun?

The sun is close to being a reliable standard illuminator.

The sun and a low power laser have about the same irradience, approx
imately one milliwatt per square millimeter.

The illumination of the bright sun can be calculated for any time of day, for any day of the year, and for any latitude. link
The resistance of the LDR varies roughly inversely with the power of the incident light.

### The Setup

The Light Dependent Resistor (LDR) was mounted behind a 7/64 diameter aperture. When the laser was shone through the apert
ure, the hole was slightly fringed with red light. The intent was that light from the sun and light from the laser would illum
inate the same area on the surface of the LDR.

### Results

Resistance due to laser light: 148.2 ohms

Resistance due to sunlight: 20.1 ohms

Sunlight power per square mm: 0.75 mw

laser power = 0.75 x 20.1 / 148.2 = 0.1 mw

## Photodiodecompared with bright sunlight

The current of the photodiode is roughly proportional to the number of photons striking it. The sensitive area is a 1 mm s
quare.

### Results

Current due to laser light: 0.081 ma

Current due to sunlight: 0.393 ma

laser power = 0.75 x 0.081 / 0.393 = 0.15 mw

### Comment

The photodiode has a huge variation in sensitivity across the spectrum of solar radiation. It is highly biased toward the
red end of the visible spectrum and near infrared. This calculation above ignores that fact.

## Photodiodeusing specifications

The datasheet gives a figure
for quantum yield (0.9 at 850 nm) plus a graph of relative sensitivity vs. wavelength.

For 640 nm (the wavelength of the laser) the electrons generated per photon is: 0.9 x 75% = 0.675.

### Calculations

The calculations for this section and the next are based on:

1 - Lumenera

2 - Strolls with my Dog

Strolls with my Dog has done excellent work uncovering the technical details of the Raspberry Pi High Quality Camera.

The following is from a jupyter notebook. It's mostly python3 code but also includes the results of print statements.

#laser wavelength

lmbda = 640e-9

#diode spectral sensitivity per datasheet

ss = 0.75

#measured current (ma)

i = 0.094e-3

#coulomb

cou = 6.24e18

#electrons per second

eps = i * cou

#conversion @ 850 nm electrons per photon

n = 0.9

#photons produced by laser beam

pp = eps / (n * ss)

#energy per photon e = h v = h c / lmbda

h = 6.63e-34

c = 3e8

ep = h * c / lmbda

#energy (watts) = photons per second x energy per photon

pwr = pp * ep

print("Laser Power = ", round(pwr*1000,2), "mw")

Laser Power = 0.27 mw

## Using the Camera to Calibrate the Laser

That's sufficiently complicated that it merits its own page. link